AP EAMCET · Maths · Area Under Curves
Area of the region (in sq. units) bounded by the curve \(y=x^2-5 x+4, x=0\), \(\mathrm{x}=2\) and the X -axis is
- A \(\frac{8}{3}\)
- B \(3\)
- C \(5\)
- D \(\frac{5}{2}\)
Answer & Solution
Correct Answer
(B) \(3\)
Step-by-step Solution
Detailed explanation
\(y=x^2-5x+4 = (x-1)(x-4)\). The curve is above the X-axis for \(x \in [0,1]\) and below for \(x \in [1,2]\). \(\text{Area} = \int_{0}^{1} (x^2-5x+4) dx + \int_{1}^{2} -(x^2-5x+4) dx\)…
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