AP EAMCET · Maths · Probability
A man is known to speak the truth 2 out of 3 times. If he throws a die and reports that it is six, then the probability that it is actually five, is
- A \(\frac{3}{8}\)
- B \(\frac{1}{7}\)
- C \(\frac{2}{7}\)
- D \(\frac{4}{5}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{7}\)
Step-by-step Solution
Detailed explanation
Let the events \(E_1=\) six occurs \(E_2=\) six does not occurs \(A=\) the mean reports that it is six. We have, \[ \begin{aligned} & P\left(E_1\right)=\frac{1}{6} \\ & P\left(E_2\right)=\frac{5}{6} \end{aligned} \] Now,…
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