AP EAMCET · Chemistry · Chemical Bonding and Molecular Structure
The bond order of dioxygen is ' \(m\) '. The bond order values of \(\mathrm{N}_2^{+}\)and \(\mathrm{C}_2^{2-}\) are respectively
- A \(\frac{5 m}{4}, \frac{3 m}{2}\)
- B \(\frac{3 m}{2}, \frac{5 m}{4}\)
- C \(\frac{m}{2}, \frac{m}{3}\)
- D \(\frac{2 m}{3}, \frac{m}{2}\)
Answer & Solution
Correct Answer
(A) \(\frac{5 m}{4}, \frac{3 m}{2}\)
Step-by-step Solution
Detailed explanation
Given that, the bond order of dioxygen is \(m\). Electronic configuration of \(\mathrm{O}_2(Z=16)=\)…
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