AP EAMCET · PHYSICS · Motion In Two Dimensions
A body projected vertically upwards crosses a point twice in its journey at a height \(h\) just after \(t_1\) and \(t_2\) seconds. Maximum height reached by the body is
- A \(\frac{g}{4}\left(t_1+t_2\right)^2\)
- B \(g\left(\frac{t_1+t_2}{4}\right)^2\)
- C \(2 g\left(\frac{t_1+t_2}{4}\right)^2\)
- D \(\frac{g}{4}\left(t_1 t_2\right)\)
Answer & Solution
Correct Answer
(C) \(2 g\left(\frac{t_1+t_2}{4}\right)^2\)
Step-by-step Solution
Detailed explanation
Time taken by the body to reach the point \(A\) is \(t_1\) (During upward journey). The body crosess this point again (during downward journey) after \(t_2\), i.e., the body takes the time \(\left(t_2-t_1\right)\) to come again at point \(A\). So, the time taken by the body to…
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