AP EAMCET · Maths · Probability
Three numbers are chosen at random from 1 to 20 , then the probability that the sum of three numbers is divisible by 3 is
- A \(\frac{1}{114}\)
- B \(\frac{147}{342}\)
- C \(\frac{16}{47}\)
- D \(\frac{32}{85}\)
Answer & Solution
Correct Answer
(D) \(\frac{32}{85}\)
Step-by-step Solution
Detailed explanation
Total number ways we can choose three integers from 20 integers \(={ }^{20} C_3\) (I) We will get all three integers are multiple of three \((3,6,9,12,15,18)={ }^6 C_3\) (II) We will get sum divisible by 3, if all three numbers when divided by 3 givens remainder of…
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