AP EAMCET · Maths · Circle
The line \(3 x+y-5=0\) touches a circle \(S\) at \((1,2)\). If \((\mathrm{h}, \mathrm{k})\) is the centre of the circle \(\mathrm{S}\) such that \(\mathrm{h}^2+\mathrm{hk}+\mathrm{k}^2=\) 37 and the radius of the circle \(\mathrm{S}\) is \(\sqrt{10}\), then \(\mathrm{k}=\)
- A \(4\)
- B \(3\)
- C \(2\)
- D \(1\)
Answer & Solution
Correct Answer
(B) \(3\)
Step-by-step Solution
Detailed explanation
\(h^2+h k+k^2=37\) ...(i) Radius \(=\sqrt{10}\) Then, equation of circle \(S^{\prime}\) is \((x-h)^2+(y-k)^2=10\) ...(ii)…
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