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AP EAMCET · Chemistry · Ionic Equilibrium

At \(27^{\circ} \mathrm{C}\). the degree of dissociation of HA (weak acid) in 0.5 M of its solution is \(1 \%\). The concentrations of \(\mathrm{H}_3 \mathrm{O}^{-}\), \(\mathrm{A}^{-}\)and HA at equilibrium (in \(\mathrm{mol} \mathrm{L}^{-1}\) ) are respectively

  1. A \(0.005,0.005,0.495\)
  2. B \(0.05,0.05,0.45\)
  3. C \(0.01,0.01,0.49\)
  4. D \(0.005,0.495,0.005\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(0.005,0.005,0.495\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & {\left[\mathrm{H}^{+}\right]=\mathrm{c} \alpha } \\ & =0.5 \times\left(10^{-2}\right) \\ & =0.005 \\ \therefore & {\left[\mathrm{H}_3 \mathrm{O}\right]^{+}=0.005 } \\ & {\left[\mathrm{~A}^{-}\right]=0.005 } \\ & {[\mathrm{HA}]=0.5-\mathrm{x} } \\ & =0.5-0.005…