AP EAMCET · Maths · Circle
If the coordinates of point, of contact of the circles \(\mathrm{x}^2+\mathrm{y}^2-4 \mathrm{x}+8 \mathrm{y}+4=0\) and \(\mathrm{x}^2+\mathrm{y}^2+2 \mathrm{x}=0\) is \((\mathrm{a}, \mathrm{b})\), then \(a+2 b=\)
- A -1
- B -2
- C 0
- D 1
Answer & Solution
Correct Answer
(B) -2
Step-by-step Solution
Detailed explanation
Circle \(x^2+y^2-4 x+8 y+4=0\) have centre \(P(2,-4)\) and radius 4 unit and circle \(x^2+y^2\) \(+2 x=0\) have centre \(Q(-1,0)\) and radius 1 unit Let \(O(a, b)\) be the point of contact.…
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