AP EAMCET · PHYSICS · Thermodynamics
The change in internal energy of given mass of a gas, when its volume changes from V to 3 V at constant pressure P is
( \(\gamma\) - Ratio of the specific heat capacities of the gas)
- A \(\frac{\mathrm{PV}}{\gamma-1}\)
- B \(\frac{2 \mathrm{PV}}{\gamma-1}\)
- C \(\frac{3 \mathrm{PV}}{\gamma-1}\)
- D \(\frac{\mathrm{PV}}{2 \gamma-1}\)
Answer & Solution
Correct Answer
(B) \(\frac{2 \mathrm{PV}}{\gamma-1}\)
Step-by-step Solution
Detailed explanation
\( \Delta U = \frac{P \Delta V}{\gamma - 1} \) \( \Delta U = \frac{P (3V - V)}{\gamma - 1} = \frac{2PV}{\gamma - 1} \)
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