AP EAMCET · Maths · Indefinite Integration
\(\int \frac{d x}{(x+1) \sqrt{4 x+3}}\) is equal to
- A \(\tan ^{-1} \sqrt{4 x+3}+c\)
- B \(3 \tan ^{-1} \sqrt{4 x+3}+c\)
- C \(2 \tan ^{-1} \sqrt{4 x+3}+c\)
- D \(4 \tan ^{-1} \sqrt{4 x+3}+c\)
Answer & Solution
Correct Answer
(C) \(2 \tan ^{-1} \sqrt{4 x+3}+c\)
Step-by-step Solution
Detailed explanation
Let \(\quad I=\int \frac{d x}{(x+1) \sqrt{4 x+3}}\) Put \(4 x+3=t^2 \Rightarrow 4 d x=2 t d t\)…
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