AP EAMCET · Maths · Straight Lines
The equation of the line passing through the point of intersection of the lines \(2 x+y-4=0, x-3 y+5=0\) and lying at a distance of \(\sqrt{5}\) units from the origin, is
- A \(x-2 y-5=0\)
- B \(x+2 y-5=0\)
- C \(x+2 y+5=0\)
- D \(x-2 y+5=0\)
Answer & Solution
Correct Answer
(B) \(x+2 y-5=0\)
Step-by-step Solution
Detailed explanation
The equation of a line passing through the in ter section of 2x + y − 4 = 0 and x − 3y + 5 = 0 is (2x + y − 4) + λ(x − 3y + 5) = 0 …(i) ⇒ x(2 + λ) + y(1 − 3λ) + 5λ − 4 = 0 This is at a distance of \(\sqrt{5}\) units from the origin.…
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