AP EAMCET · Maths · Three Dimensional Geometry
The shortest distance between the skew lines \(\mathbf{r}=(6 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}+2 \hat{\mathbf{k}})+t(\hat{\mathbf{i}}-2 \hat{\mathbf{j}}+2 \hat{\mathbf{k}})\) and \(\mathbf{r}=(-4 \hat{\mathbf{i}}-\hat{\mathbf{k}})+s(3 \hat{\mathbf{i}}-2 \hat{\mathbf{j}}-2 \hat{\mathbf{k}})\) is
- A 9
- B \(\frac{40}{7}\)
- C 108
- D 120
Answer & Solution
Correct Answer
(A) 9
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