ExamBro
ExamBro
AP EAMCET · Maths · Functions

The range of the function \(f(x)=x^2+\frac{1}{x^2+1}\) is

  1. A \([1, \infty)\)
  2. B \([2, \infty)\)
  3. C \(\left[\frac{3}{2}, \infty\right)\)
  4. D \((0,1]\)
Verified Solution

Answer & Solution

Correct Answer

(A) \([1, \infty)\)

Step-by-step Solution

Detailed explanation

Given function \(f(x)=x^2+\frac{1}{x^2+1}=y\) (let) \[ \begin{aligned} & \Rightarrow \quad x^4+x^2+1=y\left(x^2+1\right) \text { and } y>0 \\ & \Rightarrow x^4+(1-y) x^2+(1-y)=0 \end{aligned} \] \(\because x \in \mathbf{R}\), so discriminant \(\geq 0\)…