AP EAMCET · PHYSICS · Waves and Sound
Two uniform stretched steel strings \(A\) and \(B\) are vibrating under the same tension. The first overtone of \(A\) is equal to the second overtone of \(B\). If the radius of \(A\) is twice that of \(B\), then the ratio of the lengths of the strings is
- A 0.085416666666667
- B 0.043055555555556
- C 0.04375
- D 0.044444444444444
Answer & Solution
Correct Answer
(C) 0.04375
Step-by-step Solution
Detailed explanation
Frequency in stretched string, \[ f=\frac{n}{2 l} \cdot v=\frac{n}{2 l} \sqrt{\frac{T}{m}} \] where, \(l=\) length, \(T=\) tension and \(m=\) mass per unit length So, \(\quad m=\frac{\pi r^2 l \cdot d}{l}\), where, \(d=\) density and \[ m=\pi r^2 d \text {. } \] Given, \(f_A\)…
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