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AP EAMCET · Maths · Circle

The radius of the circle which cuts the circles \(x^2+y^2-4 x\) \(-4 y+7=0, x^2+y^2+4 x-4 y+6=0\) and \(x^2+y^2+4 x+\) \(4 y+5=0\) orthogonally is

  1. A \(\frac{\sqrt{193}}{4 \sqrt{2}}\)
  2. B \(\frac{\sqrt{193}}{8}\)
  3. C \(\frac{\sqrt{193}}{8}\)
  4. D \(\frac{\sqrt{193}}{2 \sqrt{2}}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{\sqrt{193}}{4 \sqrt{2}}\)

Step-by-step Solution

Detailed explanation

Let equation circle be \(x^2+y^2+2 g x+2 f y+c=0\) It is orthogonal with \(x^2+y^2-4 x-4 y+7=0\) \(\begin{aligned} & \therefore 2 g(-2)+2 f(-2)=c+7 \\ & \Rightarrow 4 g+4 f+c=-7...(i) \end{aligned}\) Also orthogonal with \(x^2+y^2+4 x-4 y+6=0\)…