AP EAMCET · Maths · Properties of Triangles
Let \(a, b\) and \(c\) denote the lengths of sides of \(B C, C A\) and \(A B\) of \(\triangle A B C\). In \(\triangle A B C, \angle B A C=30^{\circ}\) and \(\angle A B C=60^{\circ}\).
Then \(a: b: c\) is
- A \(2: \sqrt{3}: 1\)
- B \(1: \sqrt{3}: 2\)
- C \(1: 2: \sqrt{3}\)
- D \(2: 1: \sqrt{3}\)
Answer & Solution
Correct Answer
(B) \(1: \sqrt{3}: 2\)
Step-by-step Solution
Detailed explanation
Given \(B C=a, C A=b\) and \(A B=c\) To Find \(a: b: c\) \[ \begin{aligned} \because \angle A C B & =180^{\circ}-(\angle B A C+\angle A B C) \\ & =180^{\circ}-\left(30^{\circ}+60^{\circ}\right)=180^{\circ}-90^{\circ} \\ \angle A C B & =90^{\circ} \end{aligned} \] By using sine…
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