AP EAMCET · PHYSICS · Gravitation
If \(R\) is the radius of orbit of a satellite, then the kinetic energy of the satellite is
- A \(\propto \frac{1}{R}\)
- B \(\propto \frac{1}{\sqrt{R}}\)
- C \(\propto R\)
- D \(\propto \frac{1}{R^{3 / 2}}\)
Answer & Solution
Correct Answer
(A) \(\propto \frac{1}{R}\)
Step-by-step Solution
Detailed explanation
We know that, the kinetic energy of satellite revolving around a planet of radius of orbit \(R\) is \(\mathrm{KE}=\frac{G M m}{2 R}\) where, \(M=\) mass of planet, \(m=\) mass of satellite \(R=\) radius of orbit \(G=\) universal gravitational constant.…
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