AP EAMCET · Maths · Ellipse
'The product of perpendiculars from the two foci of the ellipse \(\frac{x^2}{9}+\frac{y^2}{25}=1\) on the tangent at any point on the ellipse is
- A 6
- B 7
- C 8
- D 9
Answer & Solution
Correct Answer
(D) 9
Step-by-step Solution
Detailed explanation
Given equation of ellipse is \(\frac{x^2}{9}+\frac{y^2}{25}=1\), Here \(b \gt a\) \(\begin{aligned} & \therefore c^2=b^2-a^2=25-9=16 \Rightarrow c= \pm 4 \\ & \text { foci }=(0, \pm 4) \end{aligned}\) Let the tangent be \(y=m x+C\) where…
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