AP EAMCET · Maths · Inverse Trigonometric Functions
The equation \(\cos ^{-1}(1-x)-2 \cos ^{-1} x=\frac{\pi}{2}\) has
- A no solution
- B only one solution
- C two solutions
- D more than two solutions
Answer & Solution
Correct Answer
(B) only one solution
Step-by-step Solution
Detailed explanation
Let \( \theta = \cos^{-1}x \). The equation becomes \( \cos^{-1}(1-x) = \frac{\pi}{2} + 2\theta \). Domain: \( -1 \le x \le 1 \) and \( -1 \le 1-x \le 1 \Rightarrow 0 \le x \le 2 \). Combined: \( 0 \le x \le 1 \). Range of \( \cos^{-1}y \) is \( [0, \pi] \). So…
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