AP EAMCET · Maths · Probability
The probability that a person chosen at random is left handed (in hand writing) is 0.1 . Then the probability that in a group of 10 people there is a left handed person is
- A \((0.9)^9\)
- B \((0.9)^8\)
- C \((0.9)^6\)
- D \(0.9\)
Answer & Solution
Correct Answer
(A) \((0.9)^9\)
Step-by-step Solution
Detailed explanation
\(\mathrm{p}=0.1 ; \mathrm{q}=0.9\) \(\therefore\) The probability of left handed person in a group of 10 people is: \(\begin{aligned} & \mathrm{P}={ }^{10} \mathrm{C}_1 \mathrm{p}^1 \mathrm{q}^{10-1}=10 \times 0.1 \times(0.9)^9 \\ & \Rightarrow \mathrm{P}=(0.9)^9\end{aligned}\)
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