AP EAMCET · Maths · Probability
The probability that a non-leap year contains 53 Sunday is
- A \(\frac{1}{7}\)
- B \(\frac{1}{9}\)
- C \(\frac{2}{7}\)
- D \(\frac{1}{5}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{7}\)
Step-by-step Solution
Detailed explanation
A non-leap year contains 365 days and there are total 52 weeks and 1 day in a non-leap year. Hence there should be 52 Sunday also. But the 1 extra day apart from those 52 weeks may be either Monday, Tuesday, Wednesday, Thursday, Friday, Saturday or a Sunday. Clearly, total…
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