AP EAMCET · Maths · Pair of Lines
The equation of the pair of lines is given by a second degree homogenous equation. If one of them is perpendicular to the line \(x+2 y+7=0\) and another line is parallel to the line \(3 x+4 y+5=0\), then the equation of that pair of lines is
- A \(6 x^2-5 x y+4 y^2=0\)
- B \(6 x^2+5 x y+4 y^2=0\)
- C \(6 x^2-5 x y-4 y^2=0\)
- D \(6 x^2+5 x y-4 y^2=0\)
Answer & Solution
Correct Answer
(D) \(6 x^2+5 x y-4 y^2=0\)
Step-by-step Solution
Detailed explanation
Slope of \(x+2y+7=0\) is \(m_1 = -1/2\). Equation of first line (perpendicular to \(x+2y+7=0\)): \(y - 0 = (-1/m_1)(x - 0) \implies y = 2x \implies 2x - y = 0\). Slope of \(3x+4y+5=0\) is \(m_2 = -3/4\). Equation of second line (parallel to \(3x+4y+5=0\)):…
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