AP EAMCET · Chemistry · Solid State
A compound is formed by atoms of A, B and C. Atoms of C form hcp lattice. Atoms of A occupy 50\% of octahedral voids and atoms of B occupy \(\frac{2}{3}\) rd of tetrahedral voids. What is the molecular formula of the solid?
- A \(\mathrm{A}_3 \mathrm{~B}_8 \mathrm{C}_6\)
- B \(\mathrm{A}_2 \mathrm{~B}_8 \mathrm{C}_6\)
- C \(\mathrm{AB}_4 \mathrm{C}_3\)
- D \(\mathrm{A}_5 \mathrm{~B}_8 \mathrm{C}_6\)
Answer & Solution
Correct Answer
(A) \(\mathrm{A}_3 \mathrm{~B}_8 \mathrm{C}_6\)
Step-by-step Solution
Detailed explanation
hcp contribution i.e \((C)=4\) Total octahedral void \(=4\) A contribute \(=4 \times 50 \%=2\) Total tetrahedral void \(=8 \quad \therefore B^{\prime}\) 'contribute \(=8 \times \frac{2}{3}=\frac{16}{3}\)…
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