AP EAMCET · Maths · Straight Lines
The point \(P\) is equidistant from \(A(1,3)\), \(B(-3,5)\) and \(C(5,-1)\), then \(P A\) is equal to :
- A 5
- B \(5 \sqrt{5}\)
- C 25
- D \(5 \sqrt{10}\)
Answer & Solution
Correct Answer
(D) \(5 \sqrt{10}\)
Step-by-step Solution
Detailed explanation
Let co-ordinates of \(P\) are \((x, y)\). Since, \(P\) is equidistant from \(A, B, C\), then \(P A^2=P B^2\)...(i) and \(P B^2=P C^2\)...(ii) From Eq. (i), \((x-1)^2+(y-3)^2=(x+3)^2+(y-5)^2\) \(\Rightarrow \quad x^2+1-2 x+y^2+9-6 y\) \(=x^2+9+6 x+y^2+25-10 y\)…
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