AP EAMCET · Maths · Complex Number
The multiplicative inverse of \(\mathrm{z}\) is
- A \(\frac{1}{z+\bar{z}}\)
- B \(\frac{z}{|\bar{z}|}\)
- C \(\frac{\bar{z}}{|z|^2}\)
- D \(\frac{1}{\bar{z}}\)
Answer & Solution
Correct Answer
(C) \(\frac{\bar{z}}{|z|^2}\)
Step-by-step Solution
Detailed explanation
Let multiplicative inverse of \(\mathrm{z}\), be 'A' hence \(\mathrm{z} \cdot \mathrm{A}=1\) \(\Rightarrow \quad A=\frac{1}{z}=\frac{1 \cdot \bar{z}}{z \cdot \bar{z}} \quad\) (where \(\bar{z}\) is conjugate of \(z\) )…
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