AP EAMCET · Maths · Indefinite Integration
The partial fraction of \(\frac{x^2}{x^2+3 x-4}\) is
- A \(1+\frac{-16}{5(x+4)}+\frac{1}{5(x-1)}\)
- B \(1+\frac{-1}{x+4}+\frac{1}{x-1}\)
- C \(1+\frac{-13}{5(x+4)}+\frac{1}{5(x-1)}\)
- D \(\frac{2}{x+4}+\frac{1}{x-1}\)
Answer & Solution
Correct Answer
(A) \(1+\frac{-16}{5(x+4)}+\frac{1}{5(x-1)}\)
Step-by-step Solution
Detailed explanation
\(\because \frac{x^2}{x^2+3 x-4}\)…
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