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AP EAMCET · Maths · Circle

The number of common tangents to the circles \(x^2+y^2+2 x+8 y-23=0\) and \(x^2+y^2-4 x-10 y+19=0\), is

  1. A \(1\)
  2. B \(2\)
  3. C \(3\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(3\)

Step-by-step Solution

Detailed explanation

C1 \( = (-1, -4) \), R1 \( = \sqrt{(-1)^2 + (-4)^2 - (-23)} = \sqrt{40} = 2\sqrt{10} \) C2 \( = (2, 5) \), R2 \( = \sqrt{(2)^2 + (5)^2 - 19} = \sqrt{10} \) d \( = \sqrt{(2 - (-1))^2 + (5 - (-4))^2} = \sqrt{3^2 + 9^2} = \sqrt{9 + 81} = \sqrt{90} \) R1 + R2…