AP EAMCET · Maths · Determinants
Let \(M=\left[\begin{array}{ll}1 & 1 \\ 0 & 1\end{array}\right]\) and \(N=\left[\begin{array}{ll}1 & 0 \\ 0 & 2\end{array}\right]\). Then \(N M^{10} N^{-1}=\)
- A \(\left[\begin{array}{ll}1 & 5 \\ 0 & 1\end{array}\right]\)
- B \(\left[\begin{array}{cc}1 & -5 \\ 0 & 1\end{array}\right]\)
- C \(\left[\begin{array}{cc}1 & -10 \\ 0 & 1\end{array}\right]\)
- D \(\left[\begin{array}{cc}1 & 10 \\ 0 & 1\end{array}\right]\)
Answer & Solution
Correct Answer
(A) \(\left[\begin{array}{ll}1 & 5 \\ 0 & 1\end{array}\right]\)
Step-by-step Solution
Detailed explanation
\begin{aligned} M & =\left[\begin{array}{ll} 1 & 1 \\ 0 & 1 \end{array}\right] \\ M^2 & =\left[\begin{array}{ll} 1 & 1 \\ 0 & 1 \end{array}\right]\left[\begin{array}{ll} 1 & 1 \\ 0 & 1 \end{array}\right] \\ M^2 & =\left[\begin{array}{ll} 1 & 2 \\ 0 & 1 \end{array}\right] \\ M^3…
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