AP EAMCET · Maths · Parabola
The parabola with focus at \((4,-3)\) and vertex at \((4,-1)\) is
- A \(\mathrm{x}^2+8 \mathrm{x}+6 \mathrm{y}+22=0\)
- B \(x^2-8 x-10 y+6=0\)
- C \(x^2-8 x-16 y=0\)
- D \(x^2-8 x+8 y+24=0\)
Answer & Solution
Correct Answer
(D) \(x^2-8 x+8 y+24=0\)
Step-by-step Solution
Detailed explanation
Since points \((4,-3)\) and \((4,-1)\) lie on the line \(x=\) 4. So axis of parabola is the line \(x=4\). Focus of the parabola lies below the vertex. So the parabola is downwards. \(\therefore \mathrm{a}=\sqrt{(4-4)^2+(-3+1)^2}\) (distance between focus and vertex. \[ =2 \]…
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