AP EAMCET · Maths · Three Dimensional Geometry
If \(M_1, M_2, M_3\) and \(M_4\), are respectively the magnitudes of the vectors \(\mathbf{a}_1=2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+\hat{\mathbf{k}}, \mathbf{a}_2=-3 \hat{\mathbf{i}}-4 \hat{\mathbf{j}}-4 \hat{\mathbf{k}}\), \(\mathbf{a}_3=-\hat{\mathbf{i}}+\hat{\mathbf{j}}-\hat{\mathbf{k}}, \mathbf{a}_4=-\hat{\mathbf{i}}+3 \hat{\mathbf{j}}+\hat{\mathbf{k}}\), then the correct order of \(M_1, M_2, M_3\) and \(M_4\) is
- A \(M_3 < M_1 < M_4 < M_2\)
- B \(M_3 < M_1 < M_2 < M_4\)
- C \(M_3 < M_4 < M_1 < M_2\)
- D \(M_3 < M_4 < M_2 < M_1\)
Answer & Solution
Correct Answer
(A) \(M_3 < M_1 < M_4 < M_2\)
Step-by-step Solution
Detailed explanation
Given that, \(a_1=2 \hat{i}-\hat{j}+\hat{k}\) \(\begin{aligned} & a_2=3 \hat{i}-4 \hat{j}-4 \hat{k} \\ & a_3=-\hat{i}+\hat{j}-\hat{k} \\ & a_4=-\hat{i}+3 \hat{j}+\hat{k} \end{aligned}\) As \(M_1, M_2, M_3\) and \(M_4\) are the magnitudes of the vectors…
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