AP EAMCET · Maths · Binomial Theorem
The number of non-negative integral solutions of \(\mathrm{x}_1+\mathrm{x}_2+\mathrm{x}_3+\mathrm{x}_4=10\) is
- A \(120\)
- B \(144\)
- C \(256\)
- D \(286\)
Answer & Solution
Correct Answer
(D) \(286\)
Step-by-step Solution
Detailed explanation
Given \(x_1+x_2+x_3+x_4=10\) Now non-negative solution \(\begin{aligned} & ={ }^{10+4-1} C_{4-1} \\ & ={ }^{13} C_3=\frac{13 \times 12 \times 11}{3 \times 2}=286 \end{aligned}\)
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