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AP EAMCET · Maths · Three Dimensional Geometry

If \(\vec{a}\) and \(\vec{b}\) are two vectors such that \(|\vec{a}|=|\vec{b}|=\sqrt{14}\) and \(\vec{a} \cdot \vec{b}=-7\), then \(\frac{|\vec{a} \times \vec{b}|}{|\vec{a} \cdot \vec{b}|}=\)

  1. A \(7 \sqrt{3}\)
  2. B \(\sqrt{3}\)
  3. C \(49 \sqrt{3}\)
  4. D \(\frac{\sqrt{3}}{7}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\sqrt{3}\)

Step-by-step Solution

Detailed explanation

Given, \(\vec{a} \cdot \vec{b}=-7 \Rightarrow|\vec{a}||\vec{b}| \cos \theta=7\) \(\Rightarrow \cos \theta=\frac{1}{2} \Rightarrow \tan \theta=\sqrt{3}\) Now,…