AP EAMCET · Maths · Three Dimensional Geometry
If \(\vec{a}\) and \(\vec{b}\) are two vectors such that \(|\vec{a}|=|\vec{b}|=\sqrt{14}\) and \(\vec{a} \cdot \vec{b}=-7\), then \(\frac{|\vec{a} \times \vec{b}|}{|\vec{a} \cdot \vec{b}|}=\)
- A \(7 \sqrt{3}\)
- B \(\sqrt{3}\)
- C \(49 \sqrt{3}\)
- D \(\frac{\sqrt{3}}{7}\)
Answer & Solution
Correct Answer
(B) \(\sqrt{3}\)
Step-by-step Solution
Detailed explanation
Given, \(\vec{a} \cdot \vec{b}=-7 \Rightarrow|\vec{a}||\vec{b}| \cos \theta=7\) \(\Rightarrow \cos \theta=\frac{1}{2} \Rightarrow \tan \theta=\sqrt{3}\) Now,…
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