AP EAMCET · PHYSICS · Motion In Two Dimensions
The horizontal range of a projectile projected at an angle of \(45^{\circ}\) with the horizontal is 50 m . The height of the projectile when its horizontal displacement is 20 m is
- A 18 m
- B 36 m
- C 12 m
- D 24 m
Answer & Solution
Correct Answer
(C) 12 m
Step-by-step Solution
Detailed explanation
\(\mathrm{R}=50 \mathrm{~m}, \theta=45^{\circ}\) By equation of trajectory \(y=x \tan \theta\left(1-\frac{x}{R}\right)\) At \(\mathrm{x}=20 \mathrm{~m}, \mathrm{y}=\mathrm{h}\)…
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