AP EAMCET · Maths · Probability
The mean and variance of a binomial variable are and respectively. The probability that takes values greater than , is
- A
- B
- C
- D
Answer & Solution
Correct Answer
(C)
Step-by-step Solution
Detailed explanation
Given, mean np=2 ...(i) And variance npq=1 ...(ii) From Eqs.(i) and (ii), we get q=12 ∴ p=1-q=12 From Eq.(i), n×12=2 ∴ n=4 The binomial distribution is 12+124 Now, PX>1=PX=2+PX=3+P(X=4) = 4C2122122+4C3123121+4C4124 =6+4+116 =1116
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