AP EAMCET · Maths · Determinants
The set of values of \(k\) for which the system of simultaneous equations \(\mathrm{x}+\mathrm{y}+\mathrm{kz}=1,2 \mathrm{x}+2 \mathrm{y}=3\) and \(\mathrm{x}+2 \mathrm{y}+2 \mathrm{kz}=\) \(\mathrm{k}\) has no real solution is
- A \(\{0\}\)
- B \(\mathrm{R}-\{0\}\)
- C \(\{2\}\)
- D \(\{-1,0,1\}\)
Answer & Solution
Correct Answer
(A) \(\{0\}\)
Step-by-step Solution
Detailed explanation
Given system of equation \(\begin{aligned} & x+y+k z=1...(i) \\ & 2 x+2 y=3 ...(ii)\\ & x+2 y+2 k z=k...(iii)\end{aligned}\) has no real solution…
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