AP EAMCET · Maths · Circle
The locus of centres of the circles, which cut the circles \(x^2+y^2+4 x-6 y+9\) and \(x^2+y^2-5 x+4 y+2=0\) orthogonally, is
- A \(3 x+4 y-5=0\)
- B \(9 x-10 y+7=0\)
- C \(9 x+10 y-7=0\)
- D \(9 x-10 y+11=0\)
Answer & Solution
Correct Answer
(B) \(9 x-10 y+7=0\)
Step-by-step Solution
Detailed explanation
Let the circle be Cuts the circle \(\begin{aligned} & x^2+y^2+4 x-6 y+9=0 \text { and } \\ & x^2+y^2-5 x+4 y+2=0 \end{aligned}\) orthogonally. For circle \(\begin{aligned} & x^2+y^2+4 x-6 y+9=0 \\ & 2\left(g_1 g_2+f_1 f_2\right)=c_1+c_2 \\ & 2[(g)(-2)+(f)(3)]=c+9 \end{aligned}\)…
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