AP EAMCET · Maths · Probability
If \(\mathrm{A}\) and \(\mathrm{B}\) are among 20 persons who sit at random along a round table, then the probability that there are any six persons between \(A\) and \(B\) is
- A \(\frac{1}{2}\)
- B \(\frac{5}{16}\)
- C \(\frac{2}{19}\)
- D \(\frac{2}{81}\)
Answer & Solution
Correct Answer
(C) \(\frac{2}{19}\)
Step-by-step Solution
Detailed explanation
The no. of ways in which 18 people (excluding \(A\) and \(B\) ) sit in a round table with 6 people between \(\mathrm{A} \& \mathrm{~B}={ }^{18} \mathrm{C}_6 \times 2 ! \times(13-1)\) ! Thus, probability…
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