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AP EAMCET · Maths · Parabola

The equation of the tangent to the parabola \(y^2=16 x\), which is perpendicular to the line \(3 x-4 y+5=0\) is given by

  1. A \(4 x-3 y+9=0\)
  2. B \(4 x+3 y-9=0\)
  3. C \(4 x+3 y+9=0\)
  4. D \(4 x-3 y-9=0\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(4 x+3 y+9=0\)

Step-by-step Solution

Detailed explanation

Equation of tangent to the parabola \(y^2=16 x\) which is perpendicular to the line \(3 x-4 y+5=0\). So, slope of tangent is \(\left(-\frac{4}{3}\right)\) Therefore equation of tangent is…
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