AP EAMCET · Chemistry · Structure of Atom
In the ground state of hydrogen atom. electron absorbs 1.5 times energy than the minimum energy \(\left(2.18 \times 10^{-18} \mathrm{~J}\right)\) to escape from the atom. The wavelength of the emitted electron (in m) is \(\left(m_e=9 \times 10^{-31} \mathrm{~kg}\right)\)
- A \(\frac{h \times 10^{24}}{\sqrt{1.962}}\)
- B \(\frac{h}{\sqrt{1.962}} \times 10^{23}\)
- C \(\frac{h}{\sqrt{1.962}} \times 10^{25}\)
- D \(\frac{h}{\sqrt{1.962}} \times 10^{22}\)
Answer & Solution
Correct Answer
(A) \(\frac{h \times 10^{24}}{\sqrt{1.962}}\)
Step-by-step Solution
Detailed explanation
Energy absorbed by the element \(\begin{aligned} & =1.5 \times 2.18 \times 10^{-18} \mathrm{~J} \\ & =1.5 \times 2.18 \times 10^{-18} \mathrm{kgm}^2 \mathrm{~s} \mathrm{~s}^{-2} \\ & =3.27 \times 10^{-18} \mathrm{~kg} \mathrm{~m}^2 \mathrm{~s}^{-2} \end{aligned}\) Energy…
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