AP EAMCET · Maths · Pair of Lines
The equation of the pair of lines through the point \((2,1)\) and perpendicular to the pair of lines \(4 x y+2 x+6 y+3=0\) is
- A \(x y-x-2 y+2=0\)
- B \(x y+x-2 y-2=0\)
- C \(x y+x+2 y-6=0\)
- D \(x y-x+2 y-2=0\)
Answer & Solution
Correct Answer
(A) \(x y-x-2 y+2=0\)
Step-by-step Solution
Detailed explanation
Given pair of lines, \[ \begin{aligned} & 4 x y+2 x+6 y+3=0 \\ \Rightarrow \quad & 2 x(2 y+1)+3(2 y+1)=0 \\ \Rightarrow \quad & (2 x+3)(2 y+1)=0 \end{aligned} \] So, equations of lines are \(x=\frac{-3}{2}\) and \(y=-\frac{1}{2}\) Equations of line passing through \((2,1)\) and…
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