AP EAMCET · Chemistry · Electrochemistry
The conductivity of a solution containing \(2.08 \mathrm{~g}\) of anhydrous barium chloride in \(200 \mathrm{~mL}\) solution is \(6 \times 10^{-3}\) \(\mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\). The molar conductivity of the solution (in \(\left.\mathrm{ohm}^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\right)\) is \(\underline{x} \times 10^2\). The value of \(\underline{x}\) is
(Atomic mass of \(\mathrm{Ba}=137, \mathrm{Cl}=35.5\) )
- A 1.2
- B 2.4
- C 3.6
- D 3
Answer & Solution
Correct Answer
(A) 1.2
Step-by-step Solution
Detailed explanation
Conductivity (k) \(=6 \times 10^{-3} \Omega^{-1} \mathrm{~cm}^{-1}\) \[ \mathrm{V}=200 \mathrm{~mL}=0.2 \mathrm{~L} \] mass \(=2.08 \mathrm{~g}\)…
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