AP EAMCET · Maths · Straight Lines
If \(\alpha\) is the angle made by the perpendicular drawn from origin to the line \(12 x-5 y+13=0\) with the positive \(X\)-axis in anti-clockwise direction, then \(\alpha=\)
- A \(\operatorname{Tan}^{-1} \frac{5}{12}\)
- B \(2 \pi-\operatorname{Tan}^{-1} \frac{5}{12}\)
- C \(\pi-\operatorname{Tan}^{-1} \frac{5}{12}\)
- D \(\pi+\operatorname{Tan}^{-1} \frac{5}{12}\)
Answer & Solution
Correct Answer
(C) \(\pi-\operatorname{Tan}^{-1} \frac{5}{12}\)
Step-by-step Solution
Detailed explanation
\(\text{Line: } 12x - 5y + 13 = 0\) \(\text{Normal form: } \frac{-12}{13}x + \frac{5}{13}y = 1\) \(\cos \alpha = -\frac{12}{13}, \sin \alpha = \frac{5}{13}\) \(\alpha\) is in the second quadrant. \(\alpha = \pi - \operatorname{Tan}^{-1} \left| \frac{5/13}{-12/13} \right|\)…
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