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AP EAMCET · Chemistry · Ionic Equilibrium

The solubility products of \(\mathrm{NiS}, \mathrm{ZnS}, \mathrm{CdS}\) and \(\mathrm{HgS}\) are \(4.7 \times 10^{-5}, 1.6 \times 10^{-24}, 8 \times 10^{-27}\) and \(4 \times 10^{-53}\) respectively. An aqueous solution contains \(\mathrm{Ni}^{2+}, \mathrm{Zn}^{2+}, \mathrm{Cd}^{2+}\) and \(\mathrm{Hg}^{2+}\) of equal concentration. \(\mathrm{H}_2 \mathrm{~S}\) gas was passed into this solution very slowly. The first and the last ions that precipitate as sulphides are respectively.

  1. A \(\mathrm{Ni}^{2+}, \mathrm{Hg}^{2+}\)
  2. B \(\mathrm{Hg}^{2+}, \mathrm{Cd}^{2+}\)
  3. C \(\mathrm{Zn}^{2+}, \mathrm{Hg}^{2+}\)
  4. D \(\mathrm{Hg}^{2+}, \mathrm{Ni}^{2+}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\mathrm{Hg}^{2+}, \mathrm{Ni}^{2+}\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & K_{\mathrm{sp}} \text { of } \mathrm{NiS}=4.7 \times 10^{-5} \\ & K_{\mathrm{sp}} \text { of } \mathrm{ZnS}=1.6 \times 10^{-24} \\ & K_{\mathrm{sp}} \text { of } \mathrm{CdS}=8 \times 10^{-27} \\ & K_{\mathrm{sp}} \text { of } \mathrm{HgS}=4 \times 10^{-53}…

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