AP EAMCET · Maths · Straight Lines
The equation of the circle circumscribing the triangle formed by the straight lines \(x+y=6\). \(2 x+y=4\) and \(x+2 y=5\) is given by
- A \(x^2+y^2+17 x+19 y+50=0\)
- B \(x^2+y^2-17 x-19 y+50=0\)
- C \(x^2+y^2+17 x-19 y-50=0\)
- D \(x^2+y^2-17 x+19 y-50=0\)
Answer & Solution
Correct Answer
(B) \(x^2+y^2-17 x-19 y+50=0\)
Step-by-step Solution
Detailed explanation
Equation of circle circumscribing the triangle formed by the straight lines, \(x+y=6,2 x+y=4\) and \(x+2 y=5\) is \(\begin{aligned} & (x+y-6)(2 x+y-4)+\lambda(2 x+y-4)(x+2 y-5) \\ & +\mu(x+2 y-5)(x+y-6)=0 \end{aligned}\) \(\because\) For a circle the coefficients of terms…
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