AP EAMCET · Maths · Pair of Lines
The distance between the pair of lines \(x^2+2 \sqrt{2} x y+2 y^2+4 x+4 \sqrt{2} y+1=0\), is
- A \(4 \sqrt{2}\)
- B \(2 \sqrt{2}\)
- C 2
- D \(6 \sqrt{2}\)
Answer & Solution
Correct Answer
(C) 2
Step-by-step Solution
Detailed explanation
Given, equation of pair of lines is \(x^2+2 \sqrt{2} x y+2 y^2+4 x+4 \sqrt{2} y+1=0\) The distance between the pair of lines \(a x^2+2 h x y+b y^2+2 g x+2 f y+c=0\) is given by \(d=2 \sqrt{\frac{g^2-a c}{a(a+b)}}\) Here, \(a=1, b=2, c=1, g=2\) \(\therefore\) Required distance…
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