AP EAMCET · Maths · Trigonometric Ratios & Identities
In a triangle \(\mathrm{ABC}, \tan \frac{A}{2} \tan \frac{B}{2}+\tan \frac{B}{2} \tan \frac{C}{2}+\tan \frac{C}{2} \tan \frac{A}{2}=\)
- A \(0\)
- B \(1\)
- C \(\frac{1}{2}\)
- D \(\pi\)
Answer & Solution
Correct Answer
(B) \(1\)
Step-by-step Solution
Detailed explanation
\(A+B+C=\pi\) \(\begin{aligned} & \frac{A+B}{2}=\frac{\pi-C}{2} \\ & \frac{A}{2}+\frac{B}{2}=\frac{\pi}{2}-\frac{C}{2}\end{aligned}\)…
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