AP EAMCET · Maths · Probability
A, B, C are three horses participating in a race. The Probability of horse A to win the race is twice that of horse B and probability of horse B to win is twice that of horse \(\mathrm{C}\). Then the probabilities of horses A, B and C to win the race are respectively
- A \(\frac{4}{7}, \frac{2}{7}, \frac{1}{7}\)
- B \(\frac{1}{6}, \frac{2}{6}, \frac{5}{6}\)
- C \(\frac{1}{4}, \frac{1}{2}, \frac{1}{7}\)
- D \(\frac{4}{7}, \frac{3}{7}, \frac{1}{7}\)
Answer & Solution
Correct Answer
(A) \(\frac{4}{7}, \frac{2}{7}, \frac{1}{7}\)
Step-by-step Solution
Detailed explanation
Let the probability of \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) winning are \(a, b, c\) respectively. Then, \(a+b+c=1\) ...(i) Given that, \(a=2 b \& b=2 c\) \(\therefore c=\frac{b}{2}\) From…
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