AP EAMCET · Maths · Properties of Triangles
The area (in square units) of \(\triangle A B C\) if \(\angle A=75^{\circ}, \angle B=45^{\circ}\) and \(a=2(\sqrt{3}+1)\) is
- A 6
- B \(2 \sqrt{3}\)
- C \(6-2 \sqrt{3}\)
- D \(6+2 \sqrt{3}\)
Answer & Solution
Correct Answer
(D) \(6+2 \sqrt{3}\)
Step-by-step Solution
Detailed explanation
Given, \(\angle A=75^{\circ}, \angle B=45^{\circ}\) and \(a=2(\sqrt{3}+1)\) In \(\triangle A O C, \quad \tan 60^{\circ}=\frac{x}{y} \Rightarrow \sqrt{3}=\frac{x}{y}\) \[ \Rightarrow \quad x=\sqrt{3} y \] Now, \(\quad x+y=2(\sqrt{3}+1)\)…
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