AP EAMCET · Maths · Vector Algebra
The angle between the diagonals of the parallelogram whose adjacent sides are \(2 \hat{i}+4 \hat{j}-5 \hat{k}, \hat{i}+2 \hat{j}+3 \hat{k}\) is
- A \(\cos ^{-1}\left(\frac{7}{\sqrt{69}}\right)\)
- B \(\cos ^{-1}\left(\frac{1}{7 \sqrt{69}}\right)\).
- C \(\cos ^{-1}\left(\frac{1}{7}\right)\)
- D \(\cos ^{-1}\left(\frac{31}{7 \sqrt{69}}\right)\)
Answer & Solution
Correct Answer
(D) \(\cos ^{-1}\left(\frac{31}{7 \sqrt{69}}\right)\)
Step-by-step Solution
Detailed explanation
We know that diagonal of parallelograms are \(\begin{aligned} & \vec{d}_1=\vec{a}+\vec{b}=3 \hat{i}+6 \hat{j}-2 \hat{k} \\ & \vec{d}_2=\vec{a}-\vec{b}=\hat{i}+2 \hat{j}-8 \hat{k} \end{aligned}\) Let angle between \(\vec{d}_1\) and \(\vec{d}_2\) is \(\theta\)…
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