AP EAMCET · Maths · Pair of Lines
The area (in sq. units) of the triangle formed by the lines \(x^2-3 x y+y^2=0\) and \(x+y+1=0\), is
- A \(\frac{2}{\sqrt{3}}\)
- B \(\frac{\sqrt{3}}{2}\)
- C \(5 \sqrt{2}\)
- D \(\frac{1}{2 \sqrt{5}}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{2 \sqrt{5}}\)
Step-by-step Solution
Detailed explanation
Given equations of line are \[ \begin{array}{r} x^2-3 x y+y^2=0 \\ x+y+1=0 \end{array} \] and \[ x+y+1=0 \] Let, \(m_1\) and \(m_2\) be the slope of the line \[ x^2-3 x y+y^2=2 \text {. } \]…
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